The statement form of the equation x/2 +6=7 is :
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Answer:
Class 7 - Maths - Simple Equations
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Exercise 4.1
Question 1:
Complete the last column of the table:
Class_7_Simple_Equations_Forming_Equation
Answer:
(i) x + 3 = 0
LHS = x + 3
Put x = 3, we get
LHS = 3 + 3 = 6 ≠ RHS
So, the equation is not satisfied.
(ii) x + 3 = 0
LHS = x + 3
Put x = 0, we get
LHS = 0 + 3 = 3 ≠ RHS
So, the equation is not satisfied.
(iii) x + 3 = 0
LHS = x + 3
Put x = -3, we get
LHS = -3 + 3 = 0 = RHS
So, the equation is satisfied.
(iv) x - 7 = 1
LHS = x - 7
Put x = 7, we get
LHS = 7 - 7 = 0 ≠ RHS
So, the equation is not satisfied.
(v) x - 7 = 1
LHS = x - 7
Put x = 8, we get
LHS = 8 - 7 = 1 = RHS
So, the equation is satisfied.
(vi) 5x = 25
LHS = 5x
Put x = 0, we get
LHS = 5 * 0 = 0 ≠ RHS
So, the equation is not satisfied.
(vii) 5x = 25
LHS = 5x
Put x = 5, we get
LHS = 5 * 5 = 25 = RHS
So, the equation is satisfied.
(viii) 5x = 25
LHS = 5x
Put x = -5, we get
LHS = 5 * (-5) = -25 ≠ RHS
So, the equation is not satisfied.
(ix) m/3 = 2
LHS = m/3
Put m = -6, we get
LHS = -6/3 = -2 ≠ RHS
So, the equation is not satisfied.
(x) m/3 = 2
LHS = m/3
Put m = 0, we get
LHS = 0/3 = 0 ≠ RHS
So, the equation is not satisfied.
(xi) m/3 = 2
LHS = m/3
Put m = 6, we get
LHS = 6/3 = 2 = RHS
So, the equation is satisfied.
Question 2:
Check whether the value given in the brackets is a solution to the given equation or not:
(a) n + 5 = 19 (n = 1) (b) 7n + 5 = 19 (n = -2) (c) 7n + 5 = 10 (n = 2)
(d) 4p – 3 = 13 (p = 1) (e) 4p – 3 = 13 (p = -4) (f) 4p – 3 = 13 (p = 0)
Answer:
(a) n + 5 = 19 (n = 1)
LHS = n + 5
Put n = 1 in LHS, we get
LHS = 1 + 5 = 6 ≠ RHS
So, n = 1 is not the solution of given equation.
(b)7n + 5 = 19 (n = -2)
LHS = 7n + 5
Put n = -2 in LHS, we get
LHS = 7 * (-2) + 5 = -14 + 5 = -9 ≠ RHS
So, n = -2 is not the solution of given equation.
(a) 7n + 5 = 19 (n = 2)
LHS = 7n + 5
Put n = 2 in LHS, we get
LHS = 7 * 2 + 5 = 14 + 5 = 19 = RHS
So, n = 2 is the solution of given equation.
(d) 4p – 3 = 13 (p = 1)
LHS = 4p - 13
Put p = 1 in LHS, we get
LHS = 4 * 1 - 3 = 4 - 3 = 1 ≠ RHS
So, p = 1 is not the solution of given equation.
(e) 4p – 3 = 13 (p = -4)
LHS = 4p - 13
Put p = -4 in LHS, we get
LHS = 4 * (-4) - 3 = -16 - 3 = -19 ≠ RHS
So, p = -4 is not the solution of given equation.
(f) 4p – 3 = 13 (p = 0)
LHS = 4p - 13
Put p = 0 in LHS, we get
LHS = 4 * 0 - 3 = 0 - 3 = -3 ≠ RHS
So, p = 0 is not the solution of given equation.
Question 3:
Solve the following equations by trial and error method:
(i) 5p + 2 = 17 (ii) 3m – 14 = 4
Answer:
(i) 5p + 2 = 17
Put p = 1 in LHS
5 * 1 + 2 = 5 + 2 = 7 ≠ RHS
Put p = 2 in LHS
5 * 2 + 2 = 10 + 2 = 12 ≠ RHS
Put p = 3 in LHS
5 * 3 + 2 = 15 + 2 = 17 = RHS
Hence, p = 3 is the solution of the given method.
(ii) 3m – 14 = 4
Put m = 4 in LHS
3 * 4 – 14 = 12 – 14 = -2 ≠ RHS
Put m = 5 in LHS
3 * 5 – 14 = 15 – 14 = 1 ≠ RHS
Put m = 6 in LHS
3 * 6 – 14 = 18 – 14 = 4 = RHS
Hence, m = 6 is the solution of the given method.
Question 4:
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30.
Answer:
(i) The sum of numbers x and 4 is 9.
=> x + 4 = 9
(ii) 2 subtracted from y is 8.
=> y – 2 = 8
(iii) Ten times a is 70.
=> 10a = 70
(iv) The number b divided by 5 gives 6.
=> b/5 = 6
(v) Three-fourth of t is 15.
=> 3t/4 = 15
(vi) Seven times m plus 7 gets you 77.
=> 7m + 7 = 77
(vii) One-fourth of a number x minus 4 gives 4.
=> x/4 – 4 = 4
(viii) If you take away 6 from 6 times y, you get 60.
=> 6y – 6 = 60
(ix) If you add 3 to one-third of z, you get 30.
=> z/3 + 3 = 30
Question 5:
Write the following equations in statement form:
(i) p + 4 = 15 (ii) m – 7 = 3 (iii) 2m = 7 (iv) m/5 = 3
(v) 3m/5 = 6 (vi) 3p + 4 = 25 (vii) 4p – 2 = 18 (viii) p/2 + 2 = 8
Answer:
(i) p + 4 = 15
The sum of numbers p and 4 is 15.
(ii) m – 7 = 3
7 subtracted from m is 3.
(iii) 2m = 7
Two times m is 7.
(iv) m/5 = 3
The number m is divided by 5 gives 3.
(v) 3m/5 = 6
Three-fifth of the number m is 6.
(vi) 3p + 4 = 24
Three times p plus 4 gets 25.
(vii) 4p – 2 = 18
If you take away 2 from 4 times p, you get 18.
(viii) p/2 + 2 = 8
If you added 2 to half is p, you get 8.
Question 6:
Set up an equation in the following cases:
(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles.
(Tale m to be the number of Parmit’s marbles.)
(ii) Laxmi’s father is 49 years old. He is 4 years older