The statement (-p- q n-qis 2 points
true when? *
O p: false q: false
O p: true q:false
O p: true q: true
O p: false q: true
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∨q means F∨F=F,∼r means F
∨q means F∨F=F,∼r means F∴[(∼p∨q)∧∼r)=F∧F=F which imply p=T means F⇒T=T.
∨q means F∨F=F,∼r means F∴[(∼p∨q)∧∼r)=F∧F=F which imply p=T means F⇒T=T.Hence, the truth value of the given statement is True.
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