The statement (pᴧq)→(~p) is
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Step-by-step explanation:
p. q (p^q). ~p. ( p^q) =(~p)
T. T. T. F. F
T. F. F. F. T
F. T. F. T. T
F. F. F. T. T
then ...
above statement is contigency....
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