The states of hybridization of boron and oxygen atoms in boric acid (H BO3) are respectively (1) sp3 and spa (2) sp2 and sp3 (3) spa and sp? (4) sp3 and sp3.
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Answer:
sp2 and sp2
Explanation:
Lone pair. = no. of valence electrons of central atom - electrons used to equal the corner atoms.
Hybridisation = no. of atoms attached + lone pair
H3BO3 = H3 B = 3 + 0 = 3 = sp2
= BO3 = 3 + 0 = 3 = sp2
Therefore option (c)
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