Question

The statinary waves are set up in an air column .The velocity of sound in air is 330m/s & the frequency is 165Hz.The distance between the node is

Answer 1

Answer:

heyy mate here is ur answer

Explanation:

\[v=330\] \[m/s]; \[n=165\] \[hz\](It's a formula)

so the distance between two successivenodes= \[\frac {\lambda}

{2}\]\[=frac {v}2n=\frac {330}{2\times 165}= 1m

if it is right answer plzz can u make this brainlist answer