Question

The steady current flow through a conductor is 0.5A for 2 hours. Calculate the number of electrons follow through any section of Conductor​

Answer 1

Answer:

2.25×10^-16

Explanation:

Current=0.5 A

Time=2 hours=2(60×60)= 7200

I=∆Q/∆t

∆Q=I×∆t

∆Q= 0.5×7200

∆Q= 3600

Now for Electrons:

Q=ne

n=Q/e

n=3600/1.6×10^-19

n= 2.25× 10^-16