Question

the steam point and ice point of mercury thermometer are marked as 80 degree and 20 degree .what will be the tempreture in centigrade on mercury scale when this thermometer reads 32 degree

Answer 1

This is ur ans hope it will help you in case of any doubt comment below

Answer 2

$\huge\boxed{Solution}$

$\frac{temp. \: on \: 1 \: scale - lfp}{ufp - lfp} = \frac{temp \: on \: 2 \: scale \: - lfp}{ufp \: -lfp}</p><p></p><p></p><p></p><p><strong>W</strong><strong>h</strong><strong>e</strong><strong>r</strong><strong>e</strong><strong>,</strong></p><p><strong>L</strong><strong>F</strong><strong>P</strong><strong> </strong><strong>=</strong><strong> </strong><strong>l</strong><strong>o</strong><strong>w</strong><strong>e</strong><strong>r</strong><strong> </strong><strong>f</strong><strong>i</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong> </strong><strong>p</strong><strong>o</strong><strong>i</strong><strong>n</strong><strong>t</strong><strong> </strong><strong>o</strong><strong>r</strong><strong> </strong><strong>i</strong><strong>c</strong><strong>e</strong><strong> </strong><strong>p</strong><strong>o</strong><strong>i</strong><strong>n</strong><strong>t</strong><strong> </strong><strong>a</strong><strong>n</strong><strong>d</strong><strong> </strong><strong>U</strong><strong>F</strong><strong>P</strong><strong> </strong><strong>=</strong><strong> </strong><strong>u</strong><strong>p</strong><strong>p</strong><strong>e</strong><strong>r</strong><strong> </strong><strong>f</strong><strong>i</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong> </strong><strong>p</strong><strong>o</strong><strong>i</strong><strong>n</strong><strong>t</strong><strong>.</strong></p><p></p><p></p><h3><strong>I</strong><strong>n</strong><strong> </strong><strong>m</strong><strong>o</strong><strong>r</strong><strong>e</strong><strong> </strong><strong>s</strong><strong>i</strong><strong>m</strong><strong>p</strong><strong>l</strong><strong>i</strong><strong>f</strong><strong>i</strong><strong>e</strong><strong>d</strong><strong> </strong><strong>w</strong><strong>a</strong><strong>y</strong><strong>,</strong></h3><p><strong>[tex] \frac{c - 0}{100} = \frac{f - 32}{180} = \frac{k - 273}{100}$

According to question

given

for one scale

1. temperature on given scale = 32°
2. lower fixed point of given scale = 20°
3. upper fixed point of given scale = 80°

For centegrade scale

1. Temperature = ?
2. LFP = 0°
3. UFP = 100°

________________________________________

Puting all in formula

$\frac{32 - 20}{80 - 20} = \frac{c - 0}{100 - 0} \\ \\ \frac{12}{60} \times 100 = c \\ \\ c = 20$

Therefore,

temperature on celcius scale comes out to be 20°

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Hope this helped