Question

The steamboat geyser in Yellowstone National park, Wyoming is capable of shooting it's hot water up from the ground with a speed of 48m/s. How high can this geyser shoot.​

Answer 1

Answer:

115.2m

Explanation:

Let , hight = h

Given, v = 48m/s, g = 10m/s² (use)

Now,

v² = 2gh

h = v²/2g = (48)²/(2x10) = 2304/20m

h = 115.2m.