The stoichiometric number of species from left to right in the chemical
equation
Br2 + NaOH → NaBr + NaBrO3 + H2O. When balanced respectively are :
(A) 3, 4, 3, 1, 2 (B) 1, 2, 1, 1, 2 (C) 2, 4, 3, 1, 2 (D) 3, 6, 5, 1, 3
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Write down the unbalanced equation (' skeleton equation') of the chemical ... For a better result write the reaction in ionic form. Br 2 → Br- + BrO3-. Step 2. ... Br02 → Br-1- + Br+ 5O-23
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