Question

The stoichiometry of the following reaction is K2S2O8(aq)+2KI(aq) gives 2K2SO4(aq)+I2

Answer 1

Answer: 1 : 2 is the stoichiometry of this reaction.

Explanation: Stoichiometry of any reaction is the relation between the quantities that are taking part in a reaction or forming a product.

In a given reaction,

$K_2S_2O_8(aq.)+2KI(aq.)\rightarrow 2K_2SO_4(aq.)+I_2(g)$

1 mole of $K_2S_2O_8$ and 2 moles of KI gives 2 moles of $K_2SO_4$ and 1 mole of $I_2$. So, the stoichiometry will be 1 : 2.

Answer 2

Answer:

ans is 1:2 since the ratio of reactants is 1:2