Question

the stone is droped for from
the height of h' and the same
stone is droped on the height of 4h
on another plante what
will be the acceleration due
of the gravity​

Answer 1

Let the initial velocity of stone which is thrown from the ground u
2
​
.
At maximum height 4h, Velocity v
2
​
=0
Using v
2
=u
2
−2as ⇒0=u
2
2
​
−2g×4h ⇒u
2
​
=
8gh
​
...1

Let h
1
​
be the distance covered by the stone which is dropped from height h,
Let h
2
​
be the distance covered by the stone which is thrown up from the ground.
Let at time t both stone crossed each other.

Using s=ut+
2
1
​
at
2
,
⇒−h
1
​
=−
2
1
​
gt
2
⇒h
1
​
=
2
1
​
gt
2
....2
⇒h
2
​
=u
2
​
t−
2
1
​
gt
2
....3

Adding h
1
​
and h
2
​
gives the height h.
∴ Adding equations 2 and 3,
⇒h=
2
1
​
gt
2
+u
2
​
t−
2
1
​
gt
2
⇒h=u
2
​
t

Using the value of u
2
​
=
8gh
​
,
⇒h=
8gh
​
t ⇒t=
8g
h
​

​
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