Question

the stone is thrown vertically upward with a speed of 49 MS - 1 then the velocity of the stone one second before it reaches the maximum height is​

Answer 1

Answer:

ANSWER

u= 49 m/s

five to reach top point is five to 

make  its vertically zero by qranity   

⇒time=a△v=9u−0=9.849=5sec. 

so velocity ,after 5-1=4 & of projection  

will be v= u-9t= 49−9.8×4

v=9.8m/s

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