Question

The stones are projected with the same speed but making different angles with the horizontal. there horizontal ranges are equal the angle of projection of one is π/3 the maximum height reached is 102 m them the maximum height reached by other is?

Answer 1

Answer:34m

Explanation:

Answer 2

Hi.

Range is equal for two angles α and β when:

α=90-β

It is given that α=π/3=60°

60=90-β

β=30°

Now find expression for initial velocity:

Given max height at angle 60 is 102m.

$h= u^2sin^2\alpha /2g\\102/sin^2(60)=u^2/2g\\u^2/2g=136$---Relation 1

Now we need to find:

Using relation 1:

$h=u^2sin^2(30)/2g\\h=136*(1/4)\\h=34m$