Question

the stopcock connecting the two bulbs of equal volume at pressure 2 ATM and 1 ATM is opened at constant temperature then find the final pressure of the whole system​

Answer 1

Hii Dear,

◆ Answer -

P = 3/2 atm

◆ Explaination -

# Given -

V1 = V2

P1 = 2 atm

P2 = 1 atm

# Solution -

When stopcock between 2 bulbs is opened, there will be free flow of gas from higher pressure to lower pressure until equilibrium.

Final pressure of whole system is calculated by -

P = (P1V1 + P2V2) / (V1 + V2)

P = (2V1 + V1) / (V1 + V1)

P = 3V1 / 2V1

P = 3/2 atm

Therefore, final pressure of whole system is 3/2 atm.

Thanks dear...

Answer 2

Answer:

Explanation:

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