Question

The stopping distance of a car is 10m, when moving with a speed of 40 km/h. If the car is moving with a speed of 80 km/h then its stopping distance will be

Answer 1

Answer:

Hi friend,

here is your answer

Answer 2

well I think it's a wrong question...

because the retardation would come as follows:

v^2 =u^2+2as

initial velocity : 40km/hr : 200/18 m/s

final velocity : 0 (because body comes to rest)

distance = 10 m

so retardation is :

0 = (200/18)^2 + 2 * a * 10

(-(200/18)^2) /20 = a

this value will be very very large...

and I'm not gonna calculate it X)