Question

the stopping distance of a car is 40 km when moving with the speed of 80 kilometre per hour if the car is now moving with 40 km per hour then what will be its stopping distance ​

Answer 1

Answer:

V^2 = u^2 +2as

V=final velocity =0

U= initial velocity = 40km/hr

S= distance = 2 m = 2/1000km= 0.002 km

a=acceleration

0=40^2 +2 x a x 0.002

0.004 a= - 1600

a = - 4x 10^5 negative sign indicates deceleration…

Now for 80 kmph…

V^2 = u^2 +2as

0 = 80 ^2 + 2 x (- 4x 10^5) x S

0= 0.064 x 10^5 + - 40 x 10^5 S

40s =0.064

S= 0.0016 km

1.6 metres…

Explanation:

Answer 2

Explanation:

ans =10 km

and answer is posted above