The stopping distance of vehicle is 3 m when its speed of driving is 5 m/s. What will be the stopping distance for the same vehicle if its speed is tripled (three times) ? [ Ans. 27 m ]
Answers
Answered by
0
Answer:
Explanation:
Work done = kinetic energy
Work done = braking force × distance
This means that:
So for a fixed maximum braking force, the braking distance is proportional to the square of the velocity.
Answered by
2
Answer:
27
Explanation:
Given, u=5 m/s
v=0
s=3m(at least)
By third equation by motion,
v2=u2+2as=(5×5)+2(−a)(3)=25-6a=
a= 4.17
Now applying third equation of motion,
v2=u2+2as⟹0=(15)2+2(−4.17)(s)⟹0=225−8.34s⟹s=26.970≈27.00
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