The stopping potential any matreial is 1.4 Volt. What will its threshold
wavelength if the value of incident radiation is 5.6 eV.
[h = 6.63 x 10^-34 Js, C = 3 x 10^8 m/s, eV = 1.6 10^-19 J]
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Answers
Answer:
Given:
Potential of the electrons, V = 30 kV = 3 × 104 V
Speed of light, c = 3 × 108 m/s
Energy of the electrons, E = 3 × 104 eV
Where, e = Charge on an electron = 1.6 × 10−19 C
Maximum frequency produced by the X-rays = ν
The energy of the electrons is given by the relation:
E = hν
Where, h = Planck’s constant = 6.626 × 10−34 Js
Therefore v = (E/h)
= (3 × 104 x 1.6 × 10−19)/ (6.626 × 10−34)
=7.24 x 1018 Hz
Hence, the maximum frequency of X-rays produced is 7.24 x 1018 Hz
The minimum wavelength produced by the X-rays is given as:
λ = (c/ν)
= (3 x 108)/ (7.24 x 1018)
=4.14 x 10-11 m
λ =0.0414 nm
Hence, the minimum wavelength of X-rays produced is 0.0414 nm.
Answer:
The threshold wavelength of the X ray will be 0.0414 m
Explanation:
For details please refer the attachment.
