Question

The stopping potential V₀ (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be :
(Given : Planck's constant (h) = 6.63 × 10⁻³⁴ Js, electron charge e = 1.6 × 10⁻¹⁹ C)
(A) 1.82 eV (B) 1.66 eV
(C) 2.12 eV (D) 1.95 eV

Answer 1

Explanation:

hv=ϕ+ev0

v0=ehv−eϕ

v0 is zero fro v=4×1014Hz

0=ehv−eϕ⇒ϕ=hv

=1.6×10−196.63×10−34×4×1014=1.66eV.