Question

The stopping potential (V₀) versus frequency (v) plot of a substance is shown in figure, the threshold wavelength is(a) 5 × 10¹⁴ m(b) 6000 Å(c) 5000 Å(d) Cannot be estimated from given data

Answer 1

answer is 6000A°

bcoz threshold frequency is 5×10¹⁴ Hz

then threshold wavelength is

speed of light÷ threshold wavelength

Answer 2

The threshold wavelength of the substance is $6\times 10^{-7}\ m$.

Explanation:

When the value of stooping potential is equal to 0, the corresponding frequency is called threshold frequency.

From the attached figure,

When $V_o=0$, $f_o=5\times 10^{14}\ Hz$

The corresponding threshold wavelength is given by :

$\lambda_o=\dfrac{c}{f_o}$

$\lambda_o=\dfrac{3\times 10^8\ m/s}{5\times 10^{14}\ Hz}$

$\lambda=6\times 10^{-7}\ m$

So, the threshold wavelength of the substance is $6\times 10^{-7}\ m$. Hence, this is the required solution.

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