Math, asked by arpitpatil56, 2 days ago

The stopwatch gives the reading of 40sec.The pace rating of operator &adjustment
needed due to job difficulties are 115%and 25% Resp.Calculate performance rating
to be considered to normalize observed time of operator.​

Answers

Answered by syndisksiq
0

Answer:

The stopwatch gives the reading of 40sec.The pace rating of operator &adjustment

needed due to job difficulties are 115%and 25% Resp.Calculate performance rating

to be considered to normalize observed time of operator.

Step-by-step explanation:

I don't know.

Answered by Swati3101
0

Answer:

The observed time at the rating factor 115\% and 25\% is 0.69min and 0.15min.

Step-by-step explanation:

We are given that the stopwatch reading is =40sec

Now we change this time into minutes, we get

Reading time =\frac{40}{60}

                     =0.6min

The observed time for the rating factor 115\% is =\frac{Rating factor(\%)}{100} \times reading time

=\frac{115}{100} \times 0.6

=0.69min

The observed time for the rating factor 25\% is =\frac{Rating factor(\%)}{100} \times reading time

=\frac{25}{100} \times 0.6

=0.15min

Hence, the observed time at the rating factor 115\% and 25\% is 0.69min and 0.15min.

                                                             

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