Question

The storage battery of a car has an emf of 12 V. If the internal
resistance of the battery is 0.4 12, what is the maximum current
that can be drawn from the battery?​

Answer 1

Answer:

The maximum current is given by I=

Voltage/Internal resistance

= 12/0.4

=30A

Explanation:

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Answer 2

$\huge \underline \mathrm \purple{Question↣}$

The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 12, what is the maximum current that can be drawn from the battery?

$\huge \underline \mathrm \green{Answer↣}$

In the given question,

The EMF of the battery is given as $\bold{E = 12 V}$

The internal resistance of the battery is given as $\bold{R = 0.4 Ω}$

The amount of maximum current drawn from the battery is given by = I

⠀⠀⠀⠀According to Ohm’s law,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀${\large{\boxed{\bold{E = IR}}}}$

⠀⠀⠀⠀⠀⠀Rearranging, we get,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$\Large{\boxed{\boxed{\bold{I = \frac{ E }{ R }}}}}$

Substituting values in the above equation, we get :

$\bold{\implies I = \frac{ 12 }{ 0.4 }}$

$\sf\red{ \implies I = 30 A}$

ᴛʜᴇʀᴇғᴏʀᴇ, ᴛʜᴇ ᴍᴀxɪᴍᴜᴍ ᴄᴜʀʀᴇɴᴛ ᴅʀᴀᴡɴ ғʀᴏᴍ ᴛʜᴇ ʙᴀᴛᴛᴇʀʏ ɪs 30 ᴀ