Question

The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?​

Answer 1

Given :-

• The EMF of the battery (E) = 12 V

• The internal resistance of the battery (R) = 0.4 Ω

To Find :-

• The maximum current that can be drawn from the battery?

Solution :-

According to Ohm’s law,

$\red\bigstar$E = IR

[ Putting values ]

$\implies$ 12 = I × 0.4

$\implies$ I = 12/0.4

$\implies$ I = 30 A $\green\bigstar$

Hence,

• The maximum current drawn from the given battery is 30 A.

Answer 2

Explanation:

Given:-

the EMF of battery =e=12V

internal resistance of battery =$0.4 {\Omega}$

To find:-

the maximum current that can be drawn from the battery.

Solution:-

As we know that

According to Ohm's law

${\boxed {E=IR}}$

by putting values

${:}\longrightarrow$$12=I×0.4$

${:}\longrightarrow$$I={\frac {12}{0.4}}$

${:}\longrightarrow$${\underline{\boxed{\bf {I=30A}}}}$