Question

The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?
​

Answer 1

Answer:

30 ampere

Explanation:

E=12V

r=0.4ohm

so I=E/r

12/0.4=30 ampere

Answer 2

Answer:

Emf of the battery, E = 12V

internal resistance of the battery, r = 0.4ohm

maximum current drawn from the battery = I

According to ohm's law

E = Ir

I = E/r

=$12 \div 0.4$

$= 30A$

The maximum current drawn from the given battery is 30 A.