Question

The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?
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Answer 1

Answer:

Current = 30 Amperes

Explanation:

According to the question,

• Voltage = V = 12 V
• Resistance = R = 0.4 Ω

By Ohm's Law,

    Voltage ∝ Current

⇒ Voltage = Resistance × Current

where  Resistance is a constant.

   Voltage = Resistance × Current

⇒ 12 = 0.4 × Current

⇒ Current = 12 ÷ 0.4

⇒ Current = 30 A

∴ Current that can be drawn from battery = 30 A

Answer 2

Answer:

Emf of the battery , E = 12V

Internal resistance of the battery, r = 0.4 ohm

Maximum current drawn from the battery = I

According to ohm's law,

E = Ir

I = E / r

$= 12 \div 0.4$

= 30A

The maximum current drawn from the given battery is 30 A.