The storage battery of a car has an emf of 12v ,if the internal resistance of the battery is 0.4ohm what will be the maximum current
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I = E ÷ (R+r) = 12/0.4 =30 Amp
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Answer: E = 12v Internal resistance r = 0.4 ohm Now maximum current that can be drawn from the battery = I Now applying ohms law E = Ir I =E/r = 12/0.4 = 30A
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