Question

The storage battery of a car has an emf of 18 V. If the internal resistance of the battery is 0.2Ω, what is the maximum current that can be drawn from from the battery?​

Answer 1

Answer:

90A

Explanation:

by ohm's law

v=IR

Here V=18 v

R=0.2 ohm

rearrange this as I=V/R

so,

I=18/0.2

====>90A

Answer 2

Given :

Emf of the battery, E = 18 V

Internal resistance of battery, r = 0.2Ω.

To find :

Maximum current drawn from the battery

Solution :

According to ohm's law,

The electric current passing through a conductor is directly proportional to current and resistance

E = Ir

here,

• E denotes Emf
• I denotes current
• r denotes resistance

Substituting all the given values in the formula,

➠ E = Ir

➠ 18 = (I)(0.2)

➠ I = 18/0.2

➠ I = 90A$.$

thus, the maximum current drawn from the given battery is 80A.