The storage of a car has an emf of 12 voltage in if the internal resistance of the battery is 0.4 what is the maximum current that can be drawn from the battery
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Use I = E/R2 formula
I= 12/0.4*0.4 = 75 amp
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Answer: Answer: E = 12v Internal resistance r = 0.4 ohm Now maximum current that can be drawn from the battery = I Now applying ohms law E = Ir I =E/r = 12/0.4 = 30A
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