Question

The straight line distance between A and B​

Answer 1

Answer:

AB=3√5 unit (option a)

Step-by-step explanation:

Hypotenus in each cases=√(2^2+1^2) = √5 unit

=> From 3 ∆ we get, AB=3√5 unit

Answer 2

Answer:

The straight line distance between A and B is (a) $3\sqrt{5}$.

Step-by-step explanation:

Just by drawing a straight line from A to B, we will get three right angled triangle each of side $2cm\ and\ 1cm$ .

That is three similar right angled triangles are formed when we draw a straight line from A to B , and

here given legs of each triangle, one leg is of $2cm$ and the other is of $1cm$.

Then by Pythagorean theorem we have

$hypotenuse=\sqrt{leg^{2} +leg^{2} }$

                  $=\sqrt{2^{2}+1^{2} }$

                 $=$ $\sqrt{5}$.

From the figure it is clear that  $length of AB=3$×$hypotenuse$ .

Hence straight line length of $AB=3$×$\sqrt{5}$$=3\sqrt{5}$