the straight line passing through the point (8,4) and cuts the y axis at B and x axis at A the locus of middle point of AB is
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Let locus of midpoint of AB is (α ,β )
Then, co-ordinate of point A ( 0, 2β) , and co-- ordinate of point B (2α, 0)
Equation of line AB , in intercept form ,
x/2α + y/2β = 1 , this equation satisfied (8, 4) [ ∵ line AB is passing through (8,4) ]
∴ 8/2α + 4/2β = 1
⇒ 1/α + 2/β = 1
⇒ 2α + β = αβ
Now,put α = x and β = y
Then, locus of midpoint of AB is 2x + y = xy
Then, co-ordinate of point A ( 0, 2β) , and co-- ordinate of point B (2α, 0)
Equation of line AB , in intercept form ,
x/2α + y/2β = 1 , this equation satisfied (8, 4) [ ∵ line AB is passing through (8,4) ]
∴ 8/2α + 4/2β = 1
⇒ 1/α + 2/β = 1
⇒ 2α + β = αβ
Now,put α = x and β = y
Then, locus of midpoint of AB is 2x + y = xy
sujanesh:
but its wrong answer
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here is ur answer
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