Question

the straight line with equation 2y=kx+h passes through the points (-3,6) and (1,11). Find the value of k and h​

Answer 1

Answer:

$k = \frac{2}{5} \\ h = \frac{108}{5}$

Step-by-step explanation:

$2y = kx + h \\ \\ ( - 3 \: \: \: \: \: \: \: \: 6) \: \: \: \: \: \: \: \: \: \: \: (1 \: \: \: \: \: \: \: \: 11) \\ \\ 2 \times 6 = k( - 3) + h \\ - 3k + h = 12 \\ \\ \\ 2 \times 11 = k(1) + h \\ \\ k + h = 22 \\ \\ k + h + 3k - h = 10 \\ 4k = 10 \\ \\ k = \frac{2}{5} \\ \\ \\ h = 22 - \frac{2}{5} = \frac{110 - 2 }{5} \\ \\ h = \frac{108}{5}$