Question

the strain energy per unit volume of a wire of youngs modulus y is u the tensile stress in the wire is
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Answer 1

Answer:

20units

please check the answer

Answer 2

The tensile stress of wire is  1/2 × load × extension

Let the length of the wire be = L

Let the area of cross section A is fixed at one end.

Let the stretched by suspended load = M

Let the extension of wire = x.

Young's modulus is the ratio = Y = stress/strain.

Therefore,

Young's modulus of wire , Y = FL/Ax

or, F = YAx/L

work done = W = F.dx

W = (YAx/L)dx

W = 1/2 × YAx²/L

W = 1/2 × {YAx/L} × x

W = 1/2 × F × x

Therefore, the tensile stress of wire is  1/2 × load × extension