Question

The strain energy stored in member BC of the truss,
as shown in the figure below, will be:
[Take AE = 250 kN][A is roller and B is pinned, AC = 2
m and AB = 2 m]
=
C
500 N
A
B​

Answer 1

Answer:

.

The strain energy stored in member AB of the pin-jointed truss shown in the below figure, when E and A are same for all members, is

[A]. 2P2L/AE

[B]. P2L/AE

[C].

P2L/2AE @

[D]. Zero

Answer: Option C

Explanation:

No answer