the strength of a school increase by 20% in one year and decrease by 20% in the next year is the final strength is greater or less than the original one and by how much percentage
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yes sir I am a looking for an account hour and a few half a the best of luck with in my case I the only thing one that is not the best same thing as a few
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let the initial strength of the school be x
the new strength when increased by 20% is x +(20/100)x => (120/100)x => 1.2x
when the strength is decreased by 20% then the new strength will be
1.2x - (20/100)(1.2x)
=> 1.2x - (0.2)(1.2x)
=> 1.2x - 0.24x
=> 0.96 x which is lesser than the initial strength (1x)
the new strength when increased by 20% is x +(20/100)x => (120/100)x => 1.2x
when the strength is decreased by 20% then the new strength will be
1.2x - (20/100)(1.2x)
=> 1.2x - (0.2)(1.2x)
=> 1.2x - 0.24x
=> 0.96 x which is lesser than the initial strength (1x)
ashwani53:
sorry wrong Answer is less 4 %
its the sane thing
same*
it was 1x which reduced to 0.96x
so i guess u can calculate the percentage difference
let me make it easy for u.... x-0.96x = 0.04x which can be written as (4/100)x => 4% of x has reduced
thanks
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