The strength of a school increased by 20% in 1 year and decreased by 20% in the next year . is the final strength greater or less than the original one and by how much percent.
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Lesser than 4 percent if the school strength is 100
Vickyverma:
solution plz answer is right
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let the original strength be x
increased = 20/100 × x
= x/5
Strength after increasing = x + x/5
= (5x+x)/5
= 6x/5
next year decrease in strength = 20%
decresed = (20/100) × (6x/5 )
= 6x/25
strength after decreasing = 6x/5 - 6x/25
= (30x-6x)/25
= 24x/25
therefore final strength is decresed
amount decreased = x - 24x/25
= (25x-24x)/25
= x/25
percent decreased =( x/25 ÷ x ) × 100%
= x/25 × 1/ x ×100
= 4%
Therefore strength decreases by 4%
Hope this help you...
increased = 20/100 × x
= x/5
Strength after increasing = x + x/5
= (5x+x)/5
= 6x/5
next year decrease in strength = 20%
decresed = (20/100) × (6x/5 )
= 6x/25
strength after decreasing = 6x/5 - 6x/25
= (30x-6x)/25
= 24x/25
therefore final strength is decresed
amount decreased = x - 24x/25
= (25x-24x)/25
= x/25
percent decreased =( x/25 ÷ x ) × 100%
= x/25 × 1/ x ×100
= 4%
Therefore strength decreases by 4%
Hope this help you...
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