Chemistry, asked by cutekhushicute4491, 1 year ago

The strength of an aqueous solution of sodium nitrate is 0.425g/25ml . the molarity of this solution is

Answers

Answered by tiwaavi
6
Hello Dear.

Given ⇒
Mass of the Sodium Nitrate = 0.425 g.

Molar Mass of the NaNO₃ = 85 g/mole.
[∵ 23 + 14 + 3 × 16 = 85]

Volume of the solution = 25 ml.
= 25/1000 liter.
= 0.025 liter.

Now, Using the Formula,

No. of moles of Sodium Nitrate = Mass/Molar Mass.
= 0.425/85
= 0.005 moles.


∵ Molarity = No. of moles of Sodium Nitrate/Volume of the solutions in liter.
    = 0.005/0.025 
    = 0.2 M.


Hence, the Molarity of the solution is 0.2 M.


Hope it helps.
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