Question

- The strength of bonds by 2s-2s,
2p-2p and 2p-2s overlapping has th
order
1) s-s>p-p>s-p
2) s-s>p-s>p-p
3) p-p>-p>s-s
4) p-p> s-s>p-s
​

Answer 1

ANSWER

It is explained on the basis of directional and non-directional nature of the sigma bond. As the s orbitals are non directional and can overlap from any side therefore s−s is quite a weak sigma bond. In contrast to this p orbitals are directional and p−p overlap is quite strong as compare to s−s overlap. The order of these in case of s and p is as follows.

therefore order of bond strength is: 2p−2p>2s−2p>2s−2s>1s−1s

Hope it helps

Mark the answer as BRAINLIEST if you are satisfied with the answer

Answer 2

Answer:

2.is correct answer..please mark as brainliest