Question

the strength of students in a school increased by 9% becomes 1744.Find the original strength. ​

Answer 1

Answer: 1587

Step-by-step explanation:

Let present strength be 100%.

Then previous strength = (100 - 9)% = 91%

Thus, we should find 91% of 1744.

$=\frac{91}{100} * 1744\\\\=91*1744\\=1587.04\\=1587\ (approx.)$

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Answer 2

Answer:

let the original strength be x

9% of x

= 9/100*x

increased strength = 1744

9/100*x = 1744

x= 1744*100/9

x= 19377