Question

The string of a kite is 150 m long and it makes an
angle of 60° with the horizontal. Find the height
of the kite from the ground. (Take V3 = 1.73).

Answer 1

Step-by-step explanation:

Diagram:- Refer the attachment

Given:-

• The string of the kite = 150m

• The string of the kite makes an angle 60° with the ground.

To Find:-

• The height of the kite from the ground.

Solution:-

Let " h " be the height of the kite. (AB = h)

AC be the length of the string. (AC = 150m)

The string makes an angle of 60° with the ground.

As we know that:-

$\sf \implies sin \theta = \dfrac{Opposite \: side}{Hypotenuse}$

$\sf In \: \triangle ABC:-$

$\sf \implies sin 60^\circ= \dfrac{AB}{AC}$

$\sf \implies \dfrac{\sqrt{3}}{2} = \dfrac{h}{150}$

$\sf \implies h = \dfrac{\sqrt{3}}{2} \times 150$

$\sf \implies h = \sqrt{3} \times 75$

$\sf Given, \: \sqrt{3} = 1.73$

$\sf \implies h = 1.73 \times 75$

$\sf \implies h = 129.75$

Therefore:-

$\underline{\boxed{\therefore \textsf{\textbf{ Height \: of \: the \: kite = 129.75m}}}}$