Question

the string of a pendulum is 2m. the bob is pulled side ways so that the string become horizontal and then the bob is released . what is the speed with which the bob arrive at the lowest point? assume that 10% of the initial energy is dissipated against air ressistance​

Answer 1

Answer:

Since the bob is released from rest.

therefore, the speed with whin the bob is

released is Om/s

Using energy conservation,

mgh 1/2mv^2 + mgh/10

9/10 gh 1/2 v2

v=6m/s.