Question

The string of a sitar makes 3,000 vibration in 6 sec. Find the time period and frequency of the sound produced by it..

Answer 1

Answer:

Time Period = Time taken to complete one oscillation.

Frequency = Number of oscillations/per second

Frequency = 3000/6

500Hz

Time period = 1/500second

0.002sec

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Answer 2

Given :

Number of vibration in 6 sec = 3000

To Find :

The time period and frequency of the sound produced

Solution :

Time period of oscillation of a vibrating particle is defined as the time taken by it to execute one complete oscillation.

Time taken to complete 3000 vibrations = 6 seconds

Time taken to complete 1 vibration =  $\frac{6}{3000}$ = 0.002 sec

Therefore, Time Period of the vibrating particle is 0.002 second

Frequency = $\frac{1}{Time Period}$

                  =  $\frac{1}{0.002}$

                  =  500 Hz

Therefore, the frequency is 500 Hz.