Question

The string of a violin emits a note of 205 Hz at its
correct tension. The string is tightened slightly and
then it produces six beats in two seconds with a
tuning fork of frequency 205 Hz. The frequency of
the note emitted by the taut string is​

Answer 1

Answer:

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Answer 2

Answer:

i.e., As ν ∝ √T, therefore, ferquency of vibration of string increases. As, it gives 6 beats per 2 sec, i.e., 3 beats/sec with a fork of frequency 205 Hz, hence, frequency of taut string would be 205 + 3 = 208 Hz.