Question

The string of a violin emits a note of 205 Hz when its tension is correct. The string is made slightly more taut and it produces 6 beats in 2 seconds with a tuning fork of frequency 205 Hz. The frequency of the note emitted by the taut string is

Answer 1

Here is your answer:

Explanation:

As V α  √T , therefore the frequency of vibration of the string increases.

Since  it gives 6 beats per 2 sec, i.e 205 Hz.

So the frequency of taut string would be 205+3 = 208Hz

i. e equal to 205 + 6 = 211 Hz