Physics, asked by anjananambiattil144, 23 days ago

The string of violin 36 cm long and has a mass of 0.2 g. With what

tension it must be stretched to tune 1000 Hz​

Answers

Answered by nasiyaniyas1978
2

Answer:

v = (T/(m/l))½

Therefore, T = v2(m/l)

But, v = 2l f1

So that T = 4l2f1(m/l) = 4 x 0.3 x 0.3 x 440 x 4.7 x 10-3 = 0.744 N

Answered by chandujnv002
0

Answer:

the tension required to tune a violin string to a frequency of 1000 Hz is approximately 288 N. approx

Explanation:

To determine the tension required to tune a violin string to a frequency of 1000 Hz, we can use the equation for the fundamental frequency of a stretched string:

Frequency = (1 / 2L) * √(Tension / Mass per unit length)

Where:

Frequency is the frequency of the string in hertz (Hz)

Tension is the tension on the string in newtons (N)

L is the length of the string in meters (m)

Mass per unit length is the mass of the string per meter in kilograms per meter (kg/m)

Given that the string is 36 cm long, we can convert this to meters by dividing by 100: L = 0.36 m

Given that the string has a mass of 0.2 g, we can convert this to kilograms by dividing by 1000: Mass per unit length = 0.0002 kg/m

The linear mass density of a string can be calculated by dividing the mass of the string by its length. So in this case, you would divide

0.0002 kg (mass of the string) by 0.36 m (length of the string) to get a linear mass density of 0.0005556 kg/m.

We can rearrange the equation to solve for Tension:

Tension = (Frequency^2 * Mass per unit length) * (2L)^2

Plugging in the values we know:

Tension = (1000^2 * 0.0005556 ) * (2*0.36)^2

Tension = (1000000 *  0.0005556) * (0.72)^2

Tension = 555.55556 * (0.72)^2

Tension = 288 N (approx)

So the tension on the string must be approximately 288 N to tune it to a frequency of 1000 Hz.

It's worth noting that this is the tension required to achieve a fundamental frequency of 1000 Hz, the tension required to achieve specific harmonics of that frequency may be different. It is also important to take into account that this equation is an approximation and in real-life scenario, other factors such as the string width, material and temperature also affect the tension.

To learn more about frequency from the link below

https://brainly.com/question/254161

To learn more about linear mass density  from the link below

https://brainly.in/question/11436917

#SPJ3

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