The strings of a parachute can bear a maximum tension of 72 kg-weight.By what minimum acceleration can a person of 96 kg descend by means of this parachute?
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mg - T = ma
a = (mg - T) / m
a = [(96 × 9.8) - (72 × 9.8)] / 96
a = 2.45 m/s^2
Person should descend by acceleration equal to 2.45 m/s^2
a = (mg - T) / m
a = [(96 × 9.8) - (72 × 9.8)] / 96
a = 2.45 m/s^2
Person should descend by acceleration equal to 2.45 m/s^2
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