Question

The strongest ppi – dpi back bonding is observed in
(A) CCI4
(B) SiCI4
(C) GeCl4
(D) SnCl4​

Answer 1

Answer:

option no.C is corrrct....

Answer 2

Answer:

Hence the correct option is (B) $SiCl4$

Explanation:

● Backbonding is the back donation of electrons or lone pairs to empty orbitals.

● For back bonding, an essential condition is that the element must have an empty d orbital or empty orbital from the $3rd$ and $3rd$ period onwards.

● $CCl4$ does not undergo $d\pi -p\pi$ back bonding because carbon does not contain d-orbital to accept electrons from lone pairs of chlorine.

● But $SiCl4, GeCl4$, and $SnCl4$ all show dπ-pπ back bonding because the central atom has an empty d-orbital.

● Out of these, $SiCl4$ has the strongest $d\pi -p\pi$ back bonding because the dπ orbital of silicon is near the pπ orbital of chlorine so, there is better overlapping and hence, it shows the strongest back bonding.

Hence the strongest $p\pi - d\pi$ back bonding is observed in $SiCl4$.

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