The structure of the major product formed in the following reaction in fig.1 is:
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b)
bcz CH2Cl breaks into CH2+and Cl-
as for this CH2CN is formed
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Answer:
b) The diagram is attached in picture
Explanation:
The product Benzyl Chloride when reacts with Sodium Cyanide(NaCN) in the presence of dimethylformamide(DMF) the CH2Cl bond breaks into two parts one part CH2+ and another part Cl -.
Now the next step comes as the breaking of NaCN bond it breaks as Na 2+ and CN-
Now in the last step CH2+ reacts with CN to form CH2CN.
And the product produced as the majority product is in the picture and is:
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