Question

The student of three sections
of a
a class have to stand
in rows. Each row has equal number of student. If there
are 24,36 and60 to student in three section, find the
maximum number
of
student in each row?

Answer 1

Let the original number of rows =x

Let the original number of students in each row =y

Total number of students in class = Number of students × Number of rows =xy

According to problem

Case 1

Total no of students =(y+1)(x−2)=xy

⇒xy−2y+x−2=xy

⇒x−2y=2 ...(1)

Case 2

Total no of students =(y−1)(x+3)=xy

⇒xy+3y−x−3=xy

⇒x−3y=−3 ...(2)

Subtracting eq(1) from eq(2) we get

−y=−5

⇒y=5

Putting the value of y in eq(1)

x−2(5)=2

⇒x=12

Hence we get x=12 and y=5

Total no. of students =xy=60

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Answer 2

Answer:

40 students in each row

Step-by-step explanation:

total no. of students in three section=60+36+24=120

now, there rows have equal no. of students so=120÷3=40