Question

The students apply a new force of 2.164 N and the block moves with a constant speed of 0.0055 m/s for an additional 5.5 s. How much work was done on the block during this part of experiment?
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Answer 1

Work done, W = 0.0654 J

Explanation:

Given that,

Force, F = 2.164 N

Speed, v = 0.0055 m/s

Time, t = 5.5 s

Let W is the work done on the block during this part of experiment. It is given by :

$W=F\times d$

$W=F\times v\times t$

$W=2.164\times 0.0055\times 5.5$

W = 0.0654 J

So, the work done on the block is 0.0654 Joules. Hence, this is the required solution.

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Topic : Work done

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