The students in a School can be arranged in 12,15 and 18 equal rows and also into a solid square. What is the lowest number of students that can be in the school
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27
Answer:
900 students
Step-by-step explanation:
The number we are looking for has to be
1. evenly divisible by 12, 15 & 18
and
2. be a perfect square
1---------------------
- Lets find prime factors of the given numbers:
- 12 = 2*2*3
- 15 = 3*5
- 18 = 2*3*3
- LCM(12,15,18) =2*2*3*3*5 = 180
We have met the first condition
2---------------------
The number, in the format 2^2*3^2*5 needs to be a perfect square
Since it already is a multiple of 2^2 and 3^2, we just need to add a factor of 5 to get 5^2.
180*5 = (2*3*5)^2= 900
Now we met the second condition and got the answer: 900
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